Răspunsuri

2014-07-23T13:51:39+03:00
I.
 explicitam modulul
3{2(-2x-3)+4x-32+23}<4x+36+8x-21
3(-4x-6+4x-32+23)<12x+15
3*(-15)<12x+15
-45<12x+15
12x>-60
x>-5
II
3[2(2x+3)+4x-32+23]<4x+36+8x-21
3[4x+6+4x-32+23]<12x+15
3(8x-26+23)<12x+15
24x-9<12x+15
12x<15+9
12x<24
x<2
1 5 1
2014-07-23T14:57:55+03:00
6|2x+3|+12x-96+69<4x+36+8x-21

6|2x+3|<42

|2x+3|<7

-7<2x+3<7

-10<2x<4

-5<x<2

x∈(-5; 2)