Răspunsuri

2014-07-23T12:06:39+03:00
A
a+1
a+2
a+3
a+4

a+a+1+a+2+a+3+a+4=105
5a+10=105
5a=105-10
5a=95
a=95:5
a=19

deci numerele sunt 19 20 21 22 23
-------------------------------------------
a
a+2
a+4

a+a+2+a+4=168
3a+6=168
3a=168-6
3a=162
a=162:3
a=54

Numerele sunt 54 56 58
7 5 7
2014-07-23T12:08:15+03:00
Fie numerele 
a,b,c,d,e
a+b+c+d+e=105
b=a+1
c=a+2
d=a+3
e=a+4
a+a+1+a+2+a+3+a+4=105
5a+10=105
5a=95
a=95/5
a=19
Fiind termeni consecutivi numerele sunt: 19,20,21,22,23
b)Fie :a,b,c cele 3 numere pare
a+b+c=168
b=a+2
c=a+4
a+a+2+a+4=168
3a+6=168
3a=168-6=162
a=162/3
a=54
Cele 3 numere pare consecutive sunt:54,56,58
4 5 4