Răspunsuri

2014-07-22T00:29:38+03:00
47:n= x r 2
53:n= x r 3
64:n= x r 4
Din nou , prin eliminare
n=5
47:5= 9 r 2
53:5= 10 r 3
64:5= 12 r 4
2014-07-22T01:10:03+03:00
47:n=c1 rest 2
47=nc1 +2
nc1=47-2=45

53:n=c2 rest 3
53=nc2 +3
nc2=53-3=50

64:n=c3 rest 4
64=nc3 +4
nc3=64-4=60

n=(45;50;60)
n-cel mai mic

45=3² *5
50=2 * 5²
60=2² *3 *5

n=5