Răspunsuri

2014-07-22T00:27:24+03:00
127:n=x r 7
53:n=x r 5 
76:n=x r 4
Incercam cateva numere pe rand
Prin eliminare rezulta ca n=6
pentru ca : 127:6= 20 r 7
53:6= 8 r 5
76:6= 12 r 4

2014-07-22T00:59:18+03:00
127:n=c1 rest 7
127=nc1 +7
nc1=127-7=120

53:n=c2 rest 5
53=nc2 + 5
nc2=53-5=48

76:n=c3 rest 4
76=nc3 +4
nc3=76-4=72

n=(120;48;72)
n-cel mai mic

120=2³ *3 *5
48=2⁴ *3
72=2³ *3²

n=2³ *3= 8*3=24