Răspunsuri

2014-07-13T20:36:05+03:00
A,b,c,d,e sunt numere naturale in ordine crescatoare

b=a+1
c=a+2
d=a+3
e=a+4

a+b+c+d+e=800
a+a+1+a+2+a+3+a+4=800
5a+10=800
5a=800-10
5a=790
a=790:5
a=158

b=158+1=159
c=158+2=160
d=158+3=161
e=158+4=162

a+d=158+161
maximul sumei a+d=319
0<1<2<398<399 Valoarea maxima a sumei a+d este 398.
2014-07-13T20:38:51+03:00
A+a+1+a+2+a+3+a+4=800
5a+10=800
5a=790
a=185
a+1=186
a+2=187
a+3=188
a+4=189
a+a+3=185+188=373
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