Răspunsuri

2014-07-13T17:23:47+03:00
Notam Ab=a,AO=b si BO=c, x=<BAO.
Au loc relatiile;
b^2+c^2=a^2,a+c=2b,sinx= \frac{c}{a}
c=2b-a
b^2+(2b-a)^2=a^2\\&#10;5b=4a\\&#10;b= \frac{4a}{5} \\&#10;c= \frac{8a}{5} -a= \frac{3a}{5} \\&#10;sin2x=2 \cdot sinx\cdot cosx=2\cdot \frac{c}{a} \cdot \frac{b}{a}= \frac{24}{25} &#10;
In concluzie, sin(BAD)=24/25.