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2014-07-13T09:57:35+03:00
f(0)=1\Rightarrow A(0;1)\in G_f

f(3)=2\Rightarrow B(3;2)\in G_f

Coarda AB are panta:

m_{AB}=\dfrac{y_B-y_A}{x_B-x_A}=\dfrac13

Din conditia de paralelism, rezulta ca panta tangentei la grafic = panta coardei AB, adica:

f'(x_0)=m_{AB}\Rightarrow \dfrac{1}{2\sqrt{x_0+1}}=\dfrac13\Rightarrow \dfrac{1}{4(x_0+1)}=\dfrac19\Rightarrow x_0=\dfrac54
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