Răspunsuri

2014-07-12T23:15:00+03:00
1) ab-ac=26
a(b-c)=26

a=k+1
b=k+3
c=k+5

(k+1)(k+3-k-5)=26

(k+1)*(-2)=26

k+1= -13

k= -13-1
k= -14

a= -14+1= -13

b= -14+3= -11

c= -14+5= -9

2)x=2k+2

y=2k+4

z=2k+6

(2k+2):(2k+4-2k-2)=21

2(k+1):2=21

k+1=21

k=21-1
k=20

x=2*20+2=40+2=42
y=2*20+4=40+4=44
z=2*20+6=40+6=46


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