Răspunsuri

2014-07-08T13:33:55+03:00
(√2/3 +√3/2+ 1/6) :√6   aducem la acelasi numitor  in paranteza

(2√2+3√3+1)/6 * 1/√6=

=2√2 +3√3+1/6√6
2014-07-08T13:45:51+03:00
Aducem la același numitor
(2√2 supra 6 + 3√3 supra 6 + 1 supra 6) : √6
(2√2 + 3√3 + 1) : 6 x 1 supra √6
(2√2 + 3√3+ 1) : 6 supra √6
(2√2+3√3+1)  supra radical din 6.
 \frac{ \sqrt{6} (2 \sqrt{2} +3 \sqrt{3}+ 1)  }{6}