Răspunsuri

2014-02-08T20:25:54+02:00
758:x=a rest 32  ⇒  758-32= ax⇒ax=726 
647:x =b rest 42  ⇒ 647-42=bx⇒bx=605
899: x=c rest 52  ⇒ 899-52=cx⇒cx=847

x= c.m.m.d. c. al nr 726, 605 si 847 = 121 pt ca
726=2*3*11^2
605=5*11^2
847=7*11^2
Obs. Putea fi si 11 dar trebuie sa tinem cont de faptul ca acest nr x>resturile date 32, 42,52
2 5 2