Răspunsuri

2014-07-06T23:53:42+03:00
Impartim ecuatia la cos^2 x, notam tg x =t si avem:

-3t^2-2t+1=0  cu solutiile:

t_1=-1;\ t_2=\dfrac13

tg x=-1\Rightarrow x_k=-\dfrac{\pi}{4}+k\pi;\ k\in Z

tgx= \dfrac13\Rightarrow x_k=arctg\dfrac13+k\pi; k\in Z