Răspunsuri

2014-07-05T14:07:24+03:00
Aducem la acelasi numitor si obtinem:

x+1+3+2\sqrt3=x\sqrt3+2x-2\sqrt3-4

Trecem termenii cu x in dreapta:

4\sqrt3+8=x+x\sqrt3\Rightarrow x=\dfrac{4(\sqrt3+2)}{\sqrt3+1}=\dfrac{4(\sqrt3+2)(\sqrt3-1)}{2}=2(1+\sqrt3)