Răspunsuri

2014-07-04T16:25:36+03:00
Daca x+y=1,calculati:
(2x+2y)+(3x+3y)²+(4x+4y)³=?

[2(x+y)]+[3(x+y)]^2+[4(x+y)]^3

dar cum x+y=1, avem
(2x1)+(3x1)^2+(4x1)^3=
2+3^2+4^3=
2+9+64=
=75