Răspunsuri

2014-07-02T18:35:56+03:00
1)x²+4x-x-4+2x²-4x+x-2= 3x²-6= 3(x²-2)=3(x-√2)(x+√2)

2)x³+x²-2x-2+x³-4x+x²-x-2x+2= 2x³+2x²-4x=2x(x²+x-2)=2x(x²+2x-x-2)=2x[x(x+2)-(x+2)]

=2x(x+2)(x-1)

3)x³-2x²-3x²+6x-x³-2x²+2x³+2x²+x+1= 2x³-5x²+7x+1