1) 2Fe+3Cl2=2FeCl3
Calculati masa de produs de reactie exprimata in grame care se formeaza in urma reactiei complete a 246L clor masurati la t=27°C la presiune de 3 atm

2)C3H8+5O2=3CO2 + 4H2O
Calculati cantitatea de etan exprimata in moli care prin ardere elibereaza 10211.70Jk. Se dau urmatoarele entaltipp standard H2O=-241.60 CO2=-393,20 C3H8=-103.66

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Răspunsuri

2014-06-30T21:07:54+03:00
1)nr moli = 246*3/0,082*300=30 moli
3 moli clor.....2*160,5 g clorura
30 moli clor............x grame clorura       x = 3210 g
2)delta H=3*(-393,2)+4*(-241,6)-(-103,66)=.......
Q=nr moli * delta H => nr moli = Q/delta H