Răspunsuri

2014-06-25T10:59:59+03:00
1+3+5+....+99.
1+3+5+...+2n-1=n*n
99=2n-1
2n-1=99
2n=99+1
2n=100
n=100:2
n=50

Deci 
1+3+5+....+99=50*50 

a= radical din 50*50
a= radical din 50^2
a=50 => a este nr rational
9 4 9
2014-06-25T11:41:41+03:00
1+3+5+....+99.
1+3+5+...+2n-1=n*n
99=2n-1
2n-1=99
2n=99+1
2n=100
n=100:2
n=50

3 3 3