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2014-06-18T20:39:25+03:00
X+y=162
y+z=354⇒y=354-z
x+z=408⇒x=408-z
Inlocuim in prima ecuatie
x+y=162⇒408-z+354-z=162⇒ -2z=162-762⇒ -2z= -600⇒z=300
y=354-z=354-300=54
x=408-z=408-300=108
3 5 3
2014-06-18T20:48:26+03:00
X+y=162
y+z=354
x+z=408

2x+2y+2z=162+354+408
2(x+y+z)=924
x+y+z=462

z=462-162
z=300

x=462-354
x=108

y=462-408
y=54




2 4 2