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2014-06-18T10:31:36+03:00
Rationalizam in paranteza

(4√12/12 - 6√27/27 +8√32/32)  :√2=

=(√12/3 -2√27/9 + √32/4) :√2=

= (2√3/3  -6√3/9 +4√2/4):√2=

=(2√3/3 -2√3/3 +√2):√2   aducem la acelasi numitor 

=(2√3-2√3+3√2)/3  * 1/√2=

= 3√2/3 * 1/√2=

= √2/1 * 1/√2=1