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2014-06-17T22:36:48+03:00
X²-4x>0, x(x-4)>0⇒x∈(-inf, 0)U(4, + inf)
2-x>0
x<2, x∈(-inf, 2)
din intersectia intervalelor⇒x∈(-inf, 0)
x²-4x=3(2-x)
x²-4x=6-3x
x²-x-6=0
x1,2=(1+-√1+24)2=(1+-5)/2
x1=3∉(-inf, 0)
x2=-2∈(- inf, 0)
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