Răspunsuri

2014-06-17T00:08:33+03:00
A) -7 ≤ |2x-5| ≤7

-7 ≤ 2x-5 ≤7 |5

-2 ≤ 2x ≤ 12 |:2

-1 ≤ x ≤6  ⇒A={-1,0,1,2,3,4,5,6}
x∈Z

b) -1 ≤ (4x+8)/4 <7  aducem la acelasi numitor

-4 ≤ 4x+8 < 28 |-8

-12 ≤ 4x < 20 |:4

-3 ≤ x < 5   ⇒B={0,1,2,3,4}
x∈N
1 4 1