Răspunsuri

2014-06-13T17:25:50+03:00
9-3√3+3√3.(2-√3)+(2+√3)/(4-3)=
9-3√3+6√3-9+2+√3=
4√3+2
daca ai radical din el
√(4√3+2)
= 3,71+5,19
=9
da am gresit ceva..
nu mai inteleg dar oricum bine ca a iesit.succes
ms
2014-06-13T17:31:18+03:00
√81=9
√27=3√3
| 2-√3|= 2-√3

√ (lung din) 9-3√3+3√3*(2-√3) +1/ (2-√3)   rationalizam

√ 9-3√3 +6√3-9 + (2+√3)/4-3

√ -3√3 +6√3 +2+√3

√(4√3+2) =√ (√48+2)