Răspunsuri

2014-06-13T16:21:59+03:00
Rationalizam

[ √2(√2-1)/2   -√3(√3+1)/3 + (3√2+2√3)/6]  * 3√7/ 2√5

[ (2-√2)/2 - (3+√3)/3  + (3√2+2√3)/6 ] * 3√7/2√5   aducem la acelasi numitor in paranteza

(6-3√2-6-2√3+3√2+2√3)/6 * 3√7/2√5

(6-6)/2 * √7/2√5

0/2 * √7/2√5=0
ma poti ajuta si la intrebarea precedenta te roh ?
2014-06-13T17:45:31+03:00
L-am scris in word, si l-am convertit, sper ca poti sa-l deschizi