Răspunsuri

2014-06-11T17:24:19+03:00
H_{2}SO_{4} + 2NaOH -> Na_{2}SO4 + 2H_{2}O

1 mol H2SO4 reacţionează cu .................... 2 moli NaOH
5 kmoli H2SO4 .............................................. x= 10 kmoli NaOH

Aplicăm concentraţia de 20%:

10 \  kmoli *  \frac{100}{20}  = 50 \ kmoli \ NaOH = 2000 \  kg \ NaOH
2 5 2
2014-06-11T17:38:21+03:00
2 NaOH + H2SO4 ---> Na2SO4 + 2 H2O
1 mol H2SO4........2*40 g NaOH
5 kmoli H2SO4.........x kg NaOH         x = 400 kg NaOH
c%=md/ms*100=>ms=md/c*100=400*100/20=2000 kg NaOH

masa molara NaOH = 23+16+1=40g/mol
masa molara H2SO4 = 2*1+32+4*16=98 g/mol