Răspunsuri

2014-06-10T18:55:23+03:00
1,(6)= 1 intreg 6/9 = 1 intreg 2/3 = 5/3

a+b=5/3 aducem la acelasi numitor
3a+3b=5

0,(3) = 3/9= 1/3

a-b=1/3  aducem la acelasi numitor
3a-3b=1

3a+3b=5
3a-3b=1
   adunam cele 2 ecuatii
6a =6
a=1

3*1-3b=1
3-3b=1
-3b=1-3
-3b=-2
b= 2/3
2014-06-10T18:55:27+03:00
A+b=(16-1)/9
a-b=3/9
se face sistem,rezulta 2a=18/9=2,rezulta a=2/2=1
b=15/9-1
b=6/9
b=2/3