Răspunsuri

2014-06-10T17:14:15+03:00
ΔABC, mas<A=90
AC²=BC²-AB²=20²-8² =400 -64= 336   ⇒AC=4√21

AD_|_ BC ; AD-inaltime AD-d(A;BC)

AD= AB*AC/BC

AD= 8* 4√21/20

AD= 8√21/5
6 4 6