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2014-06-10T11:40:54+03:00
BaCl2 + MgSO4 ---> BaSO4 + MgCl2
c%=md/ms*100=>md=260*20/100=52 g BaCl2
208 g BaCl2......233 g BaSO4
52 g BaCl2.........x g BaSO4          x = 58,25 g BaSO4