Răspunsuri

2014-06-09T14:57:33+03:00
A-b=161

a:b=5 rest 21
a=5b+21

5b+21-b=161
4b=161-21
4b=140
b=35

a=5*35+21= 175+21=196
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2014-06-09T15:00:55+03:00

a-b=161

a:b=5 r21

Conform teoremei inpartirii cu rest: a=5b+21

Inlcuim in prima relatie: 5b+21-b=161⇒4b=140⇒b=35⇒a=161-35=126


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