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2014-06-09T14:22:01+03:00
Construiesc AD perpendicular pe BC 
In trg ABD dreptunghic isoscel (AD=BD=x) aplic T Pitagora
x^2+x^2=(3V2)^2=18 ⇒ 2x^2=18⇒ x^2=9⇒ x=3
A trg =BC*AD/2=4V3*3/2=6V3 cm^2
Stiind aria pot sa aflu inaltime corespunzatoare laturii AB (CE)
A trg=6V3 cm^2=AB*CE/2 ⇒ CE=12V3/AB=12V3/3V2=4V3/V2=4V6/2=2V6 cm
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