Răspunsuri

2014-06-07T12:50:25+03:00
Se ia ΔVBM, unde VM-apotema piramidei M∈BC  M-mij. lui BC
BM=MC=BC/2=10/2=5

ΔVBM, mas<M=90  ⇒VM²=VB²-BM²=13²-5²=169-25=144  ⇒VM=12
1 5 1