Răspunsuri

2014-06-06T22:07:19+03:00
(x+2)/(x-1) - (x+5)/(x+1)=3  aducem la acelasi numitor

(x+2)(x+1)- (x+5)(x-1)= 3(x+1)(x-1)

x²+x+2x+2- (x²-x+5x-5)=3(x²-1)

x² +3x +2 -x²+x-5x +5= 3x²-3

4x-5x+7=3x²-3

-x+7=3x²-3

3x²-x+7+3=0

3x²-x+10=0

a=3
b=-1
c=10
Δ= 1-3*10*4= 1- 120 =-119 ⇒S{Ф}   Δnu are solutii cand are valoare negativa
1 1 1
2014-06-07T00:17:43+03:00