Răspunsuri

2014-06-06T11:09:37+03:00
Fie a, b, c cele trei numere 
abc dp cu 3, 7, 11⇔a/3=b/7=c=11=k⇒a=3k, b=7k, c=11k
dar a+b+c=3200
3k+7k+11k=3200
21k=3200
k=3200/21
a=3200/21*3=3200/7
b=3200/21*7=3200/3
c=3200/21*11
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