Răspunsuri

2014-06-06T13:17:04+03:00
Fe + 3/2 Cl2 --> FeCl3
56 g Fe.......3/2 * 2 * 35.5 g Cl2......162,5 g FeCl3
20 g Fe..............x g Cl2...................y g FeCl3
x = 38,03571 g Cl2
y = 58,03571 g FeCl3

2 Fe + 3 Cl2 ---> 2 FeCl3
2*56 g Fe.......3*2*35,5 g Cl2...........2*162,5 g FeCl3
20 g Fe.............x g Cl2........................y g FeCl3
x = 38,03571 g Cl2
y = 58,03571 g FeCl3

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