Răspunsuri

2014-06-05T14:23:48+03:00
Ducem CM _I_ AB ⇒ CM=AD si DC=AM ⇒ AM=3 cm ⇒ MB=9 cm
Aplicam teorema inaltimii in ΔACD dreptunghic in C (ipoteza) ⇒
CM ^{2} =AM*MB=3*9=27 \\ CM=3 \sqrt{3} cm
Deci AD=3√3cm
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