Răspunsuri

2014-06-04T23:18:39+03:00
X²-5x+5≤1
x²-5x+4≤0
x₁=4, x₂=1
functia este negativa intre radacini deci x∈[1,4]
2014-06-05T00:35:58+03:00
(x+1)! /(x+1-2)!=6
(x+1)! /(x-1)!=6
(x-1)!x(x+1)/(x-1)!=6 (se simplifica in fractie (x-1)!)
x(x+1)=6
x^2+x-6=0

Δ=1-24
Δ=-23⇒ ∉ R