Răspunsuri

2014-06-04T22:14:53+03:00
 MgO+ 2HCl=MgCl2(clorura de magneziu) +H2O
    Cao+HCl=CaCl(clorura de calciu)=H2O
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2014-06-04T22:21:05+03:00
20 * 200/100 = 40 g MgO
80 * 200/100 = 160 g CaO
CaO + 2 HCl ---> CaCl2 + H2O - clorura de calciu
MgO + 2 HCl ---> MgCl2 + H2O - clorura de magneziu
56 g CaO.....111 g CaCl2
160 g CaO.......x g CaCl2        x = 317,14 g CaCl2
40 g MgO.......95 g MgCl2
40 g MgO.......x g MgCl2       x = 95 g MgCl2
masa totala sare = 317.14+95=412,14 g saruri

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