Răspunsuri

2014-02-03T18:46:24+02:00
Cred ca te referi la asta :
1.  6mn+6m =   6m * (n +1)
2.  12by-9b =  3b * (4y -3)
3.  15ax+20bx =  5x* (3a + 4b)
4.  7y^{5} + 21 y^{3} = 7 y^{3} ( y^{2} + 3)
dar 7y la a 5+21y la a 3
Am updatat raspunsul cu cea in plus ceruta de tine.
2014-02-03T19:11:43+02:00
Descompui in factori prin metoda factorului cumun.
1. 6mn+6m=6m(n+1) ; 2. 12by-9b= 3b(4y-3) ; 3. 15ax+20bx= 5x(3a+4b)
 7y^{5} + 21y^{3} =7y^{3} ( y^{2} +3)