Răspunsuri

2014-06-03T17:36:27+03:00
2014-06-03T17:36:29+03:00
 \sqrt{(3x-2) ^{2} } =17 <=>3x-2=289 =>x=97  Pasi: ridicam la patrat ca sa scapam de radical dupa care egalam cele doua ecuatii.Bafta!
era +4 nu -4, scuze :D
x_1,2=(-b±√Δ)/2a
x_1=(16+34)/6=50/6
x_2=(16-34)/6=(-18)/6=-3
solutie e doar -3(doar el apartine numerelor intregi)