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2014-06-02T21:19:36+03:00
2 Al + 3 I2 --->2 AlI3
3 moli I2..........2 moli AlI3.........2*408 g AlI3
9 moli I2..........x moli AlI3..........y g AlI3
x = 6 moli AlI3
y = 2448 g AlI3
masa molara AlI3=27+3*127=408 g/mol
6 4 6