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2014-06-02T15:00:27+03:00
 \frac{2(a+3)}{(a+1)(a+3)} = \frac{2}{a+1}
a+1 I2
a+1∈D2 (multimea divizorilor lui 2)
D2={-1,+1,-2,+,-2}
a+1=-1⇒a=-2
a+1=+1⇒a=0
a+1=-2⇒a=-3
a+1=2⇒a=1
2 5 2
2014-06-02T15:18:31+03:00