Răspunsuri

2014-06-02T14:38:46+03:00
 \frac{a}{11}= \frac{b}{3}=k \\ a=11k;b=3k \\  \frac{7a-2b}{3a+5b}= \frac{7*11k-2*3k}{3*11k+5*3k}=\frac{77k-6k}{33k+15k}= \frac{71k}{48k} = \frac{71}{48}
ms , oricum l am facut inainte , dupa ce l-am scris pe site =))