Răspunsuri

2014-01-30T17:09:40+02:00
Pai daca a(a+1)(a+2)=a(a+1)+48=>a(a+1)(a+2-1)=48=>a=3,b=4,c=5
4 4 4
2014-01-30T17:28:08+02:00
Fie a-1,a, a+1 cele 3 nr consecutive

(a-1)*a*(a+1)=(a-1)*a+48
=> (a-1)*a*(a+1)-(a-1)*a=48
=> (a-1)*a(a+1-1+1)=48
=>(a-1)*a²=48
=> (a-1)*a²=3*4²
=> a=4
a-1=3
a+1=5

Rezulta ca numerele naturale consecutive sunt 3,4,5.


3 3 3