Răspunsuri

2014-05-30T19:17:13+03:00
Aplic teorema lui Pitagora generalizata
BC^2=AB^2+AC^2-2*AB*AC*cosA
AB^2=75
AC^2=25
BC^2=75+25-2*5V3*5*14V3/25=75+25-84=16
BC=4
Perimetrul=5V3+5+4=9+5V3