Răspunsuri

2014-05-28T19:40:10+03:00
{√3x-2√2y=-√6                               {√3x-2√2y=-√6
{2√3x+√2y=3√6      inmultim cu 2⇒ {4√3x+2√2y=6√6  se reduce y⇒ √3x+4√3x=6√6-√6⇒
  
5√3x=5√6  ⇒   x=5√6/5√3=√6/√3=√2√3/√3=√2 deci x=√2
y=(3√6-2√3x)/√2=(3√6-2√3·√2)/√2=(3√6-2√6)/√2=√6/√2=√3√2/√2 se simplifica⇒
y=√3
1 5 1