Răspunsuri

2014-05-28T22:24:54+03:00
⇒[(√2-1)/√2+(√3-√2)/√6+(2-√3)/2√3+(√5-2)/2√5]·5/(5-√5)=
=[(2√6-2√3+2√3-2√2+2√2-√6)/2√6+(√5-2)/2√5]·5/(5-√5)=
=[√6/2√6+(√5-2)/2√5]·5/(5-√5)=
=[1/2+(√5-2)/2√5]·5/(5-√5)=
=[(√5+√5-2)/2√5]·5/(5-√5)=
=(2√5-5)/2√5·5/(5-√5)=
=2(√5-1)/2√5·5/(5-√5)=(5√5-5)/(5√5-5)=1