Răspunsuri

2014-02-02T09:04:36+02:00
Faci n = 1 =>  z_{2} =  \sqrt{3+ \sqrt{3} } ;
Faci n = 2 =>  z_{3} =  \sqrt{3+ \sqrt{3+ \sqrt{3} } } ;
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Pana ajungi la n = 2013.