Răspunsuri

2014-05-26T19:44:42+03:00
√20=2√5
⇒(19√5-11√5)≤√20x-√20√5
8√5≤2√5x-√100
-2√5x≤-8√5-10      ·-1
x≥2(4√5-5)/2√5
x≥(4√5-5)/√5 rationalizam
x≥(20-5√5)/5  ⇒    x≥5(4-√5)/5
x≥4-√5
det. multimea solutiilor inecuatilor !
radical din5~2,24, deci x>sau =4-2,24~1,76 x apartine [4-rd5, +infinit)