Răspunsuri

2014-05-25T20:12:17+03:00
ΔABC, mas<A=90 
sin<C=60  =√3/2
sin<C=AB/BC= 6/BC

6/BC=√3/2

BC=6*2/√3=  6*2√3/3=  2*2√3=4√3

AC²=BC²-AB²=(4√3)²-6²= 48-36 =12  ⇒AC=2√3
1 5 1
2014-05-25T20:16:04+03:00
AC= x
m(B)= 30 grade ⇒BC= 2x
in triunghiul ABC aplicam teorema lui Pitagora
BC²=AC²+AB²
(2x)²=x²+6²
4x²-x²=6²
3x²=36
x²=12 ⇒ x=√12=2√3  ⇒   AC= 2√3