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2014-05-26T10:12:02+03:00
H2SO4 + BaCl2 ---> BaSO4(precipitatul) + 2 HCl
mase molare:BaSO4=137+32+64=233g/mol si HCl = 36,5 g/mol
233 g BaSO4......98 g HCl
466 g BaSO4.......x g HCl             x = 2 * 98 = 196 g/mol
c%=md/ms*100=>ms=196/20*100=980 g solutie