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2014-05-25T15:37:33+03:00
Ca + Cl2 ---> CaCl2
puritatea=masa pura/masa impura * 100=> masa pura = 80*300/100=240 g Ca
Volumul in cond normale = 22,4
40 g Ca........22,4 l Cl2
240 g Ca..........x l Cl2     x = 134,4 litri Cl2