Răspunsuri

2014-05-23T20:17:37+03:00
F(1/2)=2=> 1/2 x6+a=2 => 3+a=2=> a=-1
2014-05-23T20:18:02+03:00
A( 1/2; 2)∈G(f)  ⇒f(1/2)=2
                          f(1/2)=6*1/2+a

6*1/2 +a=2
3+a=2
a=2-3
a=-1
multumesc mult:)
n-ai pentru ce ;)
daca a=1=> 3+1=2 ???